10x^2+20=100

Solution for 10x^2+20=100 equation:

10x^2+20=100

We move all terms to the left:

10x^2+20-(100)=0

We add all the numbers together, and all the variables

10x^2-80=0

a = 10; b = 0; c = -80;
Δ = b2-4ac
Δ = 02-4·10·(-80)
Δ = 3200
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3200}=\sqrt{1600*2}=\sqrt{1600}*\sqrt{2}=40\sqrt{2}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-40\sqrt{2}}{2*10}=\frac{0-40\sqrt{2}}{20}
=-\frac{40\sqrt{2}}{20}
=-2\sqrt{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+40\sqrt{2}}{2*10}=\frac{0+40\sqrt{2}}{20}
=\frac{40\sqrt{2}}{20}
=2\sqrt{2}
$